查看“Module:ScheduleList”的源代码

local p = {}

-- 工具函数：判断是否为闰年
local function is_leap_year(year)
    return (year % 4 == 0 and year % 100 ~= 0) or (year % 400 == 0)
end

-- 工具函数：计算每月天数
local function days_in_month(month, year, leap_year)
    local days = {31, leap_year and 29 or 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}
    return days[month]
end

-- 工具函数：计算下一个日期
local function get_next_date(date, leap_year)
    local month, day = date:match("(%d+)月(%d+)日")
    month = tonumber(month)
    day = tonumber(day)
    
    local days_in_current_month = days_in_month(month, nil, leap_year)
    if day == days_in_current_month then
        day = 1
        month = month + 1
        if month > 12 then
            month = 1
        end
    else
        day = day + 1
    end
    
    return string.format("%d月%d日", month, day)
end

-- 工具函数：计算下一周的周几
local function get_next_weekday(weekday)
    local weekdays = {"周一", "周二", "周三", "周四", "周五", "周六", "周日"}
    return weekdays[(weekday % 7) + 1]
end

-- 主函数
function p.main(frame)
    local args = frame:getParent().args
    
    -- 获取初始参数
    local date = args.date
    local week = tonumber(args.week)
    local leap_year = args.leap_year == "yes"
    local time_defaults = {}
    
    -- 如果没有输入初始日期，则报错
    if not date then return "请提供初始日期 (date 参数)！" end
    if not week or week < 1 or week > 7 then return "请提供正确的初始周几 (week 参数，1~7)！" end
    
    -- 初始化结果表
    local result = {}
    local current_date = date
    local current_weekday = week
    
    -- 循环生成7行
    for i = 1, 7 do
        local title = args["title" .. i] or "无" -- 未提供标题时默认 "无"
        local time = args["time" .. i] or "2:00" -- 未提供时间时默认 "2:00"
        local week_day = get_next_weekday(current_weekday - 1) -- 计算周几
        
        -- 格式化当前行
        table.insert(result, string.format("{{ruby|%s|%s}}<small>%s</small> %s", current_date, time, week_day, title))
        
        -- 更新日期和周几
        current_date = get_next_date(current_date, leap_year)
        current_weekday = (current_weekday % 7) + 1
    end
    
    -- 返回结果
    return table.concat(result, "\n")
end

return p